Group A-Assignment no 5

Problem Statement:

Write a C++ program create a calculator for an arithmetic operator (+, -, *, /). The program should take two operands from user and performs the operation on those two operands depending upon the operator entered by user. Use a switch statement to select the operation. Finally, display the result. Some sample interaction with the program might look like this: Enter first number, operator, second number: 10 / 3 Answer = 3.333333 Do another (y/n)? y Enter first number, operator, second number: 12 + 100 Answer = 112 Do another (y/n)? n

Answer:

We will create program using class and objects .

Follow the following steps:

1. Create class Calculator .
2. Define three data members named operand1(int/double),operand2(int/double),operator(char)
3. Define a constructor to initialize data members.
4. Define input function to assign values to data members.(It can be used optionally)
5. Define a Function to display the result.

Program:

#include <iostream>

using namespace std;

class calculator

{

private:

int operand1,operand2,result;

char oprator;

public:

//Default Constructor

calculator()

{

operand1=0;

operand2=0;

oprator='+';

}

//Parameterised Constructor

calculator(int op1,int op2,char opr)

{

operand1=op1;

operand2=op2;

oprator=opr;

}

int doCalculation()

{

    result=0;

switch(oprator)

{

case '+':

result=operand1+operand2;

break;

case '-':

result=operand1-operand2;

break;

case '*':

result=operand1*operand2;

break;

case '/':

result=operand1/operand2;

break;

}

return result;

}

void display()

{

cout<<operand1<<" "<<oprator<<" "<<operand2<<"  =  "<<result;

}

};

int main()

{

int x=0;

int o1,o2;

char opr;

do{

cout<<"\nEnter the expression in format(operand1 oprator operand2)";

cin>>o1>>opr>>o2; 

//Object Creation

calculator c(o1,o2,opr);

//Calling the member functions

c.doCalculation();

c.display();

//To continue non-negative number is taken if -1 is entered then exit

cout<<"\nTo continue enter positive number else -1";

cin>>x;

}

while(x!=-1);

return 0;

}